Master this deck with 52 terms through effective study methods.
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decrease because atomic radius increases, distance between nucleus and bonding pair of electrons increases, less energy to remove
decreases as atomic radius increases, distance between nucleus and outer shell of electrons increases, attraction between them decreases, harder to gain an electron
oxidising agents, as they gain electrons and are reduced
from chlorine to iodine the bond enthalpy decreases because the atomic radius is larger, so the distance from the nuclei to bonding pair of electrons increases, so weaker attraction and the orbitals also overlap less effectively leading to weaker attraction. Florine is lower because its so small, the bonding pair of electrons in the outer shell repel
form metal halides, which are white, ionic solids
forms sodium chloride, sodium chlorate (1) and water
forms sodium chloride, sodium chlorate (V) and water
disproportionation
forms potassium chloride and iodine solution
add hexane and a lilac band should appear
orange and lilac because iodine and bromine are the least reactive
hydrogen fluoride has the highest because it has has hydrogen bonds between molecules. Strongest IMF Boiling point increases from HCl to HI as there are more electrons, so the London forces are stronger
add silver nitrate and nitric acid. A white precipitate should appear
add silver nitrate and nitric acid. A cream precipitate should appear
add silver nitrate and nitric acid. A yellow precipitate should appear
they are colourless gases that form misty fumes when they are in moist air
Form acids HF forms a weak acid HCl and HBr form stronger acids
You dip a rod in ammonia and put it into the misty fumes to make an ammonium halide salt.
appears as white smoke but is actually very fine powder (solid)
add a dilute acid and carbon dioxide will form. Turns limewater cloudy
add dilute hydrochloric acid add barium chloride a white precipitate should form
add sodium hydroxide and ammonia should be produced. If dipped in damp red litmus paper it turns blue
fluorine because it has the smallest atomic radius and will be reduced and gain electrons easier
iodine because it will lose electrons and oxidise as it has the largest ionic radius
its a non-redox reaction because chlorine isn't a strong enough reducing agent.
Produces a hydrogen chloride (misty fumes) and XHS04 where X is a metal
non redox- HBr (misty fumes) and XHS04 redox - S02 and Br2 and H20 formed
sulfur dioxide is a colourless, choking gas
a brown liquid/ orange fumes
redox - S02 + I2 + H20 redox- S + I2 + H20 redox - H2S + I2 + H20
a black solid with purple fumes
a yellow solid
a colourless eggy gas
shiny grey
brown
fluorine is more electronegative as it has less shielding and a smaller atomic radius due to less shells. So HF is more polar
Water can form up to 2 hydrogen bonds but HF can only form 1
Fluorine and chlorine
pale yellow
pale green
brown liquid
liquid
solid
black solid (with purple vapours when heated)
brown
purple
black solid
Orange/brown
Orange
The conc sulfuric acid is too strong of an oxidising agent and will form Iodine
the gas would dissolve
gas