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The maximum allowable voltage drop for the main vertical building conductor is 5 V.
The residential building has eight floors.
There are three residential units on each floor.
The installed power of each apartment is 4.6 kW.
The total power of the common areas is 16 kW.
The total power consumption (P_c) for the building is calculated as 126.4 kW.
The power considering the simultaneity factor (P_s) is 88.48 kW.
The current (I) is calculated using the formula I = P_s / (3 x U_f), resulting in 128.2 A.
The resistance (R) is calculated using the formula R = ΔU / I, which gives R = 0.039 Ω.
The resistivity of aluminum (ρ_Al) is 0.028 Ω × mm² × m⁻¹.
The resistivity of copper (ρ_Cu) is 0.0178 Ω × mm² × m⁻¹.
The cross-section area of the aluminum conductor (S_al) is calculated using the formula S_al = ρ * 2 * l / R, resulting in 70 mm².
The cross-section area of the copper conductor (S_cu) is calculated using the formula S_cu = ρ * 2 * l / R, resulting in 50 mm².
The length of the main vertical building conductor is 40 m.
The simultaneity factor (β) accounts for the likelihood that not all electrical loads will be used at the same time, reducing the total power requirement.
The total number of apartments in the building is 24, calculated as 3 apartments per floor multiplied by 8 floors.
The total power consumption of the apartments (P_b) is calculated as 4.6 kW multiplied by 24 apartments, resulting in 110.4 kW.
The formula used to calculate the total power consumption (P_c) is P_c = P_b x (3 floors x 8 apartments) + P_sp.
Calculating the cross-section of the conductors ensures that they can safely carry the required current without excessive voltage drop or overheating.
The relationship is defined by Ohm's law, where voltage drop (ΔU) equals current (I) multiplied by resistance (R).